This Leetcode problem Sales Person LeetCode Solution is done in SQL.

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Sales Person LeetCode Solution

Problem Statement

Column Name	Type
sales_id	int
name	varchar
salary	int
commission_rate	int
hire_date	date

sales_id is the primary key (column with unique values) for this table. Each row of this table indicates the name and the ID of a salesperson alongside their salary, commission rate, and hire date.

Column Name	Type
com_id	int
name	varchar
city	varchar

com_id is the primary key (column with unique values) for this table. Each row of this table indicates the name and the ID of a company and the city in which the company is located.

Column Name	Type
order_id	int
order_date	date
com_id	int
sales_id	int
amount	int

order_id is the primary key (column with unique values) for this table. com_id is a foreign key (reference column) to com_id from the Company table.
sales_id is a foreign key (reference column) to sales_id from the SalesPerson table.
Each row of this table contains information about one order. This includes the ID of the company, the ID of the salesperson, the date of the order, and the amount paid.

Write a solution to find the names of all the salespersons who did not have any orders related to the company with the name “RED”.

Return the result table in any order.

The result format is in the following example.

Example 1:
Input:

sales_id	name	salary	commission_rate	hire_date
1	John	100000	6	4/1/2006
2	Amy	12000	5	5/1/2010
3	Mark	65000	12	12/25/2008
4	Pam	25000	25	1/1/2005
5	Alex	5000	10	2/3/2007

com_id	name	city
1	RED	Boston
2	ORANGE	New York
3	YELLOW	Boston
4	GREEN	Austin

order_id	order_date	com_id	sales_id	amount
1	1/1/2014	3	4	1000
2	2/1/2014	4	5	5000
3	3/1/2014	1	1	50000
4	4/1/2014	1	4	25000

Output:

name

Amy

Mark

Alex

Explanation: According to orders 3 and 4 in the Orders table, it is easy to tell that only salespersons John and Pam have sales to company RED, so we report all the other names in the table salespersons.

Sales Person LeetCode Solution MySQL

select 
  s.name 
from 
  salesperson as s 
where 
  s.sales_id not in(
    select 
      sales_id 
    from 
      orders as o 
      left join company as c on o.com_id = c.com_id 
    where 
      c.name = 'RED'
  );Code language: SQL (Structured Query Language) (sql)