Last updated on January 22nd, 2025 at 11:17 pm
Here, we see the Last Person to Fit in the Bus LeetCode Solution. This Leetcode problem is solved using MySQL and Pandas.
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Level of Question
Medium

Last Person to Fit in the Bus LeetCode Solution
Table of Contents
1. Problem Statement
Column Name | Type |
person_id | int |
person_name | varchar |
weight | int |
turn | int |
Queue
person_id column contains unique values. This table has the information about all people waiting for a bus.
The person_id and turn columns will contain all numbers from 1 to n, where n is the number of rows in the table.
turn determines the order of which the people will board the bus, where turn=1 denotes the first person to board and turn=n denotes the last person to board.
weight is the weight of the person in kilograms.
There is a queue of people waiting to board a bus. However, the bus has a weight limit of 1000
kilograms, so there may be some people who cannot board.
Write a solution to find the person_name
of the last person that can fit on the bus without exceeding the weight limit. The test cases are generated such that the first person does not exceed the weight limit.
The result format is in the following example.
Example 1:
Input:
person_id | person_name | weight | turn |
5 | Alice | 250 | 1 |
4 | Bob | 175 | 5 |
3 | Alex | 350 | 2 |
6 | John Cena | 400 | 3 |
1 | Winston | 500 | 6 |
2 | Marie | 200 | 4 |
Output:
person_name |
John Cena |
Explanation: The following table is ordered by the turn for simplicity.
Turn | ID | Name | Weight | Total Weight |
1 | 5 | Alice | 250 | 250 |
2 | 3 | Alex | 350 | 600 |
3 | 6 | John Cena | 400 | 1000 (last person to board) |
4 | 2 | Marie | 200 | 1200 (cannot board) |
5 | 4 | Bob | 175 | _____ |
6 | 1 | Winston | 500 | _____ |
2. Code Implementation in Different Languages
2.1 Last Person to Fit in the Bus MySQL
select q1.person_name from Queue as q1 join Queue as q2 on q1.turn >= q2.turn group by q1.turn having sum(q2.weight) <= 1000 order by sum(q2.weight) desc limit 1;