# Rotate Image LeetCode Solution

Here, We see Rotate Image LeetCode Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc., with different approaches.

# List of all LeetCode Solution

## Problem Statement

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

```Example 1: (fig-1)
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]```
```Example 2: (fig-2)
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]```

## Rotate Image Leetcode Solution C++

``````class Solution {
public:
void rotate(vector<vector<int>>& matrix) {
int n = matrix.size();

for(int i=0; i<n; i++)
{
for(int j=i; j<n; j++)
{
int temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
for(int i=0; i<n; i++)
{
reverse(matrix[i].begin(), matrix[i].end());
}
}
};
```Code language: C++ (cpp)```

## Rotate Image Leetcode Solution Java

``````class Solution {
public void rotate(int[][] matrix) {
for(int i = 0; i<matrix.length; i++){
for(int j = i; j<matrix[0].length; j++){
int temp = 0;
temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
for(int i =0 ; i<matrix.length; i++){
for(int j = 0; j<matrix.length/2; j++){
int temp = 0;
temp = matrix[i][j];
matrix[i][j] = matrix[i][matrix.length-1-j];
matrix[i][matrix.length-1-j] = temp;
}
}
}
}
```Code language: Java (java)```

## Rotate Image Leetcode Solution JavaScript

``````var rotate = function(matrix) {
let n = matrix.length, depth = ~~(n / 2)
for (let i = 0; i < depth; i++) {
let len = n - 2 * i - 1, opp = n - 1 - i
for (let j = 0; j < len; j++) {
let temp = matrix[i][i+j]
matrix[i][i+j] = matrix[opp-j][i]
matrix[opp-j][i] = matrix[opp][opp-j]
matrix[opp][opp-j] = matrix[i+j][opp]
matrix[i+j][opp] = temp
}
}
};
```Code language: JavaScript (javascript)```

## Rotate Image Leetcode Solution Python

``````class Solution(object):
def rotate(self, matrix):
l = 0
r = len(matrix) -1
while l < r:
matrix[l], matrix[r] = matrix[r], matrix[l]
l += 1
r -= 1
for i in range(len(matrix)):
for j in range(i):
matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
```Code language: Python (python)```
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