Group Anagrams LeetCode Solution

Here, We see Group Anagrams problem Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc., with different approaches.

Group Anagrams LeetCode Solution

Group Anagrams LeetCode Solution

Problem Statement ->

Given an array of strings strs, group the anagrams together. You can return the answer in any order.

An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.

Example 1:
Input: strs = ["eat","tea","tan","ate","nat","bat"]
Output: [["bat"],["nat","tan"],["ate","eat","tea"]]
Example 2:
Input: strs = [""]
Output: [[""]]

Example 3:
Input: strs = ["a"]
Output: [["a"]]

Group Anagrams Leetcode Solution C++ ->

class Solution {
    vector<vector<string>> groupAnagrams(vector<string>& strs) {
        unordered_map<string, vector<string>> mp;
        for (string s : strs) {
            string t = s; 
            sort(t.begin(), t.end());
        vector<vector<string>> anagrams;
        for (auto p : mp) { 
        return anagrams;
Code language: C++ (cpp)

Group Anagrams Leetcode Solution Java ->

class Solution {
    public List<List<String>> groupAnagrams(String[] strs) {
        HashMap<String,List<String>> map=new HashMap<>();
        for(int i=0;i<strs.length;i++){
            String s1=strs[i];
            char[] arr=s1.toCharArray();
            String str=new String(arr);
                map.put(str,new ArrayList<>());
        return new ArrayList<>(map.values());       
Code language: Java (java)

Group Anagrams Leetcode Solution JavaScript ->

var groupAnagrams = function(strs) {
    let res = {};
    for (let str of strs) {
        let count = new Array(26).fill(0);
        for (let char of str) count[char.charCodeAt()-97]++;
        let key = count.join("#");
        res[key] ? res[key].push(str) : res[key] = [str];
    return Object.values(res);
Code language: JavaScript (javascript)

Group Anagrams Leetcode Solution Python ->

class Solution(object):
    def groupAnagrams(self, strs):
        hashmap = {}
        for st in strs:
            key = ''.join(sorted(st))
            if key not in hashmap:
                hashmap[key] = [st]
                hashmap[key] += [st]
        return hashmap.values()
Code language: Python (python)