Last updated on October 9th, 2024 at 10:35 pm
Here, We see Remove Duplicates from Sorted Array II LeetCode Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc. with different approaches.
List of all LeetCode Solution
Topics
Array, Two-Pointers
Companies
Level of Question
Medium
Remove Duplicates from Sorted Array II LeetCode Solution
Table of Contents
Problem Statement
Given an integer array nums
sorted in non-decreasing order, remove some duplicates in-place such that each unique element appears at most twice. The relative order of the elements should be kept the same.
Since it is impossible to change the length of the array in some languages, you must instead have the result be placed in the first part of the array nums
. More formally, if there are k
elements after removing the duplicates, then the first k
elements of nums
should hold the final result. It does not matter what you leave beyond the first k
elements.
Return k
after placing the final result in the first k
slots of nums
.
Do not allocate extra space for another array. You must do this by modifying the input array in-place with O(1) extra memory.
Custom Judge:
The judge will test your solution with the following code:
int[] nums = [...]; // Input array
int[] expectedNums = [...]; // The expected answer with correct length
int k = removeDuplicates(nums); // Calls your implementation
assert k == expectedNums.length;
for (int i = 0; i < k; i++) {
assert nums[i] == expectedNums[i];
If all assertions pass, then your solution will be accepted.
Example 1: Input: nums = [1,1,1,2,2,3] Output: 5, nums = [1,1,2,2,3,_] Explanation: Your function should return k = 5, with the first five elements of nums being 1, 1, 2, 2 and 3 respectively. It does not matter what you leave beyond the returned k (hence they are underscores). Example 2: Input: nums = [0,0,1,1,1,1,2,3,3] Output: 7, nums = [0,0,1,1,2,3,3,_,_] Explanation: Your function should return k = 7, with the first seven elements of nums being 0, 0, 1, 1, 2, 3 and 3 respectively. It does not matter what you leave beyond the returned k (hence they are underscores).
1. Remove Duplicates from Sorted Array II Leetcode Solution C++
class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size()<=2) return nums.size(); int count=1,j=1; for(int i=1;i<nums.size();i++){ if(nums[i-1]==nums[i]) count++; else count=1; if(count<=2) nums[j++]=nums[i]; } return j; } };
2. Remove Duplicates from Sorted Array II Leetcode Solution Java
class Solution { public int removeDuplicates(int[] nums) { int i = 0; for (int n : nums) if (i < 2 || n > nums[i - 2]) nums[i++] = n; return i; } }
3. Remove Duplicates from Sorted Array II Leetcode Solution JavaScript
var removeDuplicates = function(nums) { let j = 0; let i = 0; for (; i < nums.length; i += 1){ if (nums[i] !== nums[i + 2]) { nums[j] = nums[i]; j += 1; } } return j; };
4. Remove Duplicates from Sorted Array II Leetcode Solution Python
class Solution(object): def removeDuplicates(self, nums): k = 0 for i in nums: if k < 2 or i != nums[k - 2]: nums[k] = i k += 1 return k