# Number of Transactions per Visit LeetCode Solution

This Leetcode problem Number of Transactions per Visit LeetCode Solution is done in SQL.

# List of all LeetCode Solution

## Problem Statement

(user_id, visit_date) is the primary key for this table.
Each row of this table indicates that user_id has visited the bank in visit_date.

There is no primary key for this table, it may contain duplicates.
Each row of this table indicates that user_id has done a transaction of amount in transaction_date.
It is guaranteed that the user has visited the bank in the transaction_date.(i.e The Visits table contains (user_id, transaction_date) in one row)

A bank wants to draw a chart of the number of transactions bank visitors did in one visit to the bank and the corresponding number of visitors who have done this number of transaction in one visit.

Write an SQL query to find how many users visited the bank and didn’t do any transactions, how many visited the bank and did one transaction and so on.

The result table will contain two columns:
transactions_count which is the number of transactions done in one visit.
visits_count which is the corresponding number of users who did
transactions_count in one visit to the bank.
transactions_count should take all values from 0 to max(transactions_count) done by one or more users.
Order the result table by transactions_count.

The result format is in the following example.

Example 1:
Input:

Output:

Explanation:
– For transactions_count = 0, The visits (1, “2020-01-01”), (2, “2020-01-02”), (12, “2020-01-01”) and (19, “2020-01-03”) did no transactions so visits_count = 4.
– For transactions_count = 1, The visits (2, “2020-01-03”), (7, “2020-01-11”), (8, “2020-01-28”), (1, “2020-01-02”) and (1, “2020-01-04”) did one transaction so visits_count = 5.
– For transactions_count = 2, No customers visited the bank and did two transactions so visits_count = 0.
– For transactions_count = 3, The visit (9, “2020-01-25”) did three transactions so visits_count = 1.
– For transactions_count >= 4, No customers visited the bank and did more than three transactions so we will stop at transactions_count = 3

## Number of Transactions per Visit LeetCode Solution MySQL

``````select
(
select
0
) as transactions_count,
count(*) as visits_count
from
Visits
where
(user_id, visit_date) not in (
select
user_id,
transaction_date
from
Transactions
)
union
select
s.transactions_count,
if(
visits_count is null, 0, visits_count
) as visits_count
from
(
select
tc as transactions_count
from
(
select
t.user_id,
@tc := @tc + 1 as tc
from
Transactions as t,
(
select
@tc := 0
) as u
) as s
where
tc <= (
select
ifnull(
max(transactions_count),
0
)
from
(
select
count(*) as transactions_count
from
Transactions
group by
user_id,
transaction_date
) as t
)
) as s
left join (
select
transactions_count,
count(*) as visits_count
from
(
select
count(*) as transactions_count
from
Transactions
group by
user_id,
transaction_date
) as t
group by
transactions_count
) as t on s.transactions_count = t.transactions_count
order by
transactions_count;```Code language: SQL (Structured Query Language) (sql)```
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