# Department Top Three Salaries LeetCode Solution

This Leetcode problem Department Top Three Salaries LeetCode Solution is done in SQL.

# List of all LeetCode Solution

## Problem Statement

id is the primary key (column with unique values) for this table. departmentId is a foreign key (reference column) of the ID from the `Department `table. Each row of this table indicates the ID, name, and salary of an employee. It also contains the ID of their department.

id is the primary key (column with unique values) for this table. Each row of this table indicates the ID of a department and its name.

A company’s executives are interested in seeing who earns the most money in each of the company’s departments. A high earner in a department is an employee who has a salary in the top three unique salaries for that department.

Write a solution to find the employees who are high earners in each of the departments.

Return the result table in any order.

The result format is in the following example.

Example 1:
Input:

Output:

Explanation:
In the IT department:
– Max earns the highest unique salary
– Both Randy and Joe earn the second-highest unique salary
– Will earns the third-highest unique salary

In the Sales department:
– Henry earns the highest salary
– Sam earns the second-highest salary
– There is no third-highest salary as there are only two employees

## Department Top Three Salaries LeetCode Solution MySQL

``````select
d.name as department,
e1.name as employee,
e1.salary as Salary
from
Employee e1
join Department d on e1.DepartmentId = d.Id
where
3 > (
select
count(
distinct (e2.Salary)
)
from
Employee e2
where
e2.Salary > e1.Salary
and e1.DepartmentId = e2.DepartmentId
)
```Code language: JavaScript (javascript)```

## Department Top Three Salaries LeetCode Solution Pandas

``````import pandas as pd

def top_three_salaries(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:
return employee[employee.groupby('departmentId').salary.rank(method='dense',ascending=False)<=3].merge(department,
left_on='departmentId',right_on='id').rename(columns={'name_y':'Department','name_x':'Employee'}).iloc[:,[5,1,2]]```Code language: JavaScript (javascript)```
Scroll to Top