Last updated on October 6th, 2024 at 08:36 pm

Here, We see Super Washing Machines LeetCode Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc. with different approaches.

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Super Washing Machines LeetCode Solution

Problem Statement

You have n super washing machines on a line. Initially, each washing machine has some dresses or is empty.

For each move, you could choose any m (1 <= m <= n) washing machines, and pass one dress of each washing machine to one of its adjacent washing machines at the same time.

Given an integer array machines representing the number of dresses in each washing machine from left to right on the line, return the minimum number of moves to make all the washing machines have the same number of dresses. If it is not possible to do it, return -1.

Example 1:
Input: machines = [1,0,5]
Output: 3
Explanation: 1st move: 1 0 <– 5 => 1 1 4 2nd move: 1 <– 1 <– 4 => 2 1 3 3rd move: 2 1 <– 3 => 2 2 2

Example 2:
Input: machines = [0,3,0]
Output: 2
Explanation: 1st move: 0 <– 3 0 => 1 2 0 2nd move: 1 2 –> 0 => 1 1 1

Example 3:
Input: machines = [0,2,0]
Output: -1
Explanation: It’s impossible to make all three washing machines have the same number of dresses.

1. Super Washing Machines LeetCode Solution C++

class Solution {
public:
    int findMinMoves(vector<int>& machines) {
        int sum = 0, n = machines.size();
        for(auto &i: machines)sum += i;
        if(sum%n)return -1;
        sum /= n;
        int k = 0;
        int ans = 0;
        for(auto &i: machines){
            k += i-sum;
            ans = max({(i-sum),ans,abs(k)});
        }
        return ans;
    }
};

2. Super Washing Machines LeetCode Solution Java

class Solution {
    public int findMinMoves(int[] machines) {
        int avg = 0;
        for(int i = 0; i < machines.length; i++){
            avg += machines[i];  
        }
        if(avg % machines.length != 0){
            return -1;
        }
        int res = 0, cnt = 0;
        avg = avg / machines.length;
        for (int m : machines) {
            cnt += m - avg;
            res = Math.max(res, Math.max(Math.abs(cnt), m - avg));
        }
        return res;
    }
}

3. Super Washing Machines LeetCode Solution JavaScript

var findMinMoves = function(machines) {
    let load, tot = 0, max = 0;
    let sum = machines.reduce((a, x) => a + x);
    let target = sum / machines.length;
    if (target % 1) return -1;
    machines.forEach(n => {
        load = n - target;
        tot += load;
        max = Math.max(max, Math.abs(tot), load);
    })
    return max;    
};

4. Super Washing Machines LeetCode Solution Python

class Solution(object):
    def findMinMoves(self, machines):
        n = len(machines)
        Sum = sum(machines)
        if Sum % n:
            return -1 
        final = Sum//n
        moves = prefix = 0
        for i in machines:
            diff = i - final
            prefix += diff
            moves = max(moves, abs(prefix), diff)
        return moves