Remove Duplicates from Sorted Array LeetCode Solution

/ Leetcode Solution / Array, Bloomberg, C++ Solution, Easy, Facebook, Java Solution, JavaScript Solution, LeetCode Solution, Microsoft, Python Solution, Two Pointers

Here, We see Remove Duplicates from Sorted Array problem Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc.

List of all LeetCode Problem Solution
Remove Duplicates from Sorted Array LeetCode Solution

Remove Duplicates from Sorted Array

Problem Statement ->

Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once.

The relative order of the elements should be kept the same.

Example 1:
Input: nums = [1,1,2]
Output: 2, nums = [1,2,_]

Example 2:
Input: nums = [0,0,1,1,1,2,2,3,3,4]
Output: 5, nums = [0,1,2,3,4,_,_,_,_,_]

Remove Duplicates from Sorted Array Leetcode Solution C++ ->

class Solution {
public:
    int removeDuplicates(vector<int>& nums) {
        nums.erase(std::unique(nums.begin(), nums.end()), nums.end());
        return nums.size();
    }
};
Code language: C++ (cpp)

Remove Duplicates from Sorted Array Leetcode Solution Java->

class Solution {
    public int removeDuplicates(int[] nums) {
        if (nums.length == 0) return 0;
    int i = 0;
    for (int j = 1; j < nums.length; j++) {
        if (nums[j] != nums[i]) {
            i++;
            nums[i] = nums[j];
        }
    }
    return i + 1;
    }
}
Code language: Java (java)

Remove Duplicates from Sorted Array Leetcode Solution JavaScript ->

var removeDuplicates = function(nums) {
    let c=1
    for(let i=1;i<nums.length;i++){
        if(nums[i]==nums[i-1])continue
        nums[c]=nums[i]
        c++
    }
    let l=nums.length-1
    while(l>=c){
        nums.pop()
        l--
    }
};
Code language: JavaScript (javascript)

Remove Duplicates from Sorted Array Leetcode Solution Python ->

class Solution:
    def removeDuplicates(self, nums):
        len_ = 1
        if len(nums)==0:
            return 0
        for i in range(1,len(nums)):
            if nums[i] != nums[i-1]:
                nums[len_] = nums[i]
                len_ +=1
        return len_
Code language: Python (python)

Related Posts