Here, We see Remove Comments LeetCode Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc. with different approaches.

# List of all LeetCode Solution

## Problem Statement

Given a C++ program, remove comments from it. The program source is an array of strings source where source[i] is the ith line of the source code. This represents the result of splitting the original source code string by the newline character ‘\n’.

• The string “//” denotes a line comment, which represents that it and the rest of the characters to the right of it in the same line should be ignored.
• The string “/*” denotes a block comment, which represents that all characters until the next (non-overlapping) occurrence of “*/” should be ignored. (Here, occurrences happen in reading order: line by line from left to right.) To be clear, the string “/*/” does not yet end the block comment, as the ending would be overlapping the beginning.

The first effective comment takes precedence over others.

• For example, if the string “//” occurs in a block comment, it is ignored.
• Similarly, if the string “/*” occurs in a line or block comment, it is also ignored.

If a certain line of code is empty after removing comments, you must not output that line: each string in the answer list will be non-empty.

There will be no control characters, single quote, or double quote characters.

• For example, source = “string s = “/* Not a comment. */”;” will not be a test case.

Also, nothing else such as defines or macros will interfere with the comments.

It is guaranteed that every open block comment will eventually be closed, so “/*” outside of a line or block comment always starts a new comment.

Finally, implicit newline characters can be deleted by block comments. Please see the examples below for details.

After removing the comments from the source code, return the source code in the same format.

Example 1:
Input: source = [“/*Test program */”, “int main()”, “{ “, ” // variable declaration “, “int a, b, c;”, “/* This is a test”, ” multiline “, ” comment for “, ” testing */”, “a = b + c;”, “}”]
Output: [“int main()”,”{ “,” “,”int a, b, c;”,”a = b + c;”,”}”]
Explanation: The line by line code is visualized as below:
/*Test program */
int main()
{
// variable declaration
int a, b, c;
/* This is a test multiline comment for testing */
a = b + c;
}
The string /* denotes a block comment, including line 1 and lines 6-9. The string // denotes line 4 as comments. The line by line output code is visualized as below:
int main() {
int a, b, c;
a = b + c;
}

Example 2:
Input: source = [“a/*comment”, “line”, “more_comment*/b”]
Output: [“ab”]
Explanation: The original source string is “a/*comment\nline\nmore_comment*/b”, where we have bolded the newline characters. After deletion, the implicit newline characters are deleted, leaving the string “ab”, which when delimited by newline characters becomes [“ab”].

## Remove Comments LeetCode Solution C++

``````class Solution {
public:
vector<string>ans;
string s;
int j;
bool comment=false;
for(int i=0;i<source.size();i++){
for( j=0;j<source[i].size();j++){
if(comment==false & j+1<source[i].size() && source[i][j]=='/' && source[i][j+1]=='/') {
break;
}
else if(comment==false & j+1<source[i].size() & source[i][j]=='/' & source[i][j+1]=='*'){
comment=true;
j++;
}
else if(comment && j+1 < source[i].size() & source[i][j]=='*' & source[i][j+1]=='/') {
comment = false, j++;
}
else if(comment==false){
s.push_back(source[i][j]);
}
}
if(comment==false && s.size()){
ans.push_back(s);
s.clear();
}
}
return ans;
}
};```Code language: PHP (php)```

## Remove Comments LeetCode Solution Java

``````class Solution {
boolean blockActive = false;
List<String> result = new ArrayList<String>();
StringBuilder builder = new StringBuilder();
for(String line: source){
if(!blockActive){
builder = new StringBuilder();
}
for(int i=0; i<line.length(); i++){
char c = line.charAt(i);
if(!blockActive){
if(c=='/'){
if(i<line.length()-1 && line.charAt(i+1)=='/'){
break;
} else if(i<line.length()-1 && line.charAt(i+1)=='*'){
i++;
blockActive = true;
} else{
builder.append(c);
}
} else  {
builder.append(c);
}
} else {
if(c=='*'){
if(i<line.length()-1 && line.charAt(i+1)=='/'){
blockActive = false;
i++;
}
}
}
}
if(!blockActive && builder.length()!=0){
}
}
return result;
}
}```Code language: JavaScript (javascript)```

## Remove Comments LeetCode Solution JavaScript

``````var removeComments = function(source) {
let result = [];
let multi_line_comment = false;
let str = "";
source.forEach(line => {
for(let idx=0; idx < line.length; ++idx) {
if(!multi_line_comment) {
if(line[idx] + line[idx+1] === '//') {
break;
}
else if(line[idx] + line[idx+1] === '/*') {
multi_line_comment = true;
++idx;
}
else {
str += line[idx];
}
}
else {
if(line[idx] + line[idx+1] === '*/') {
multi_line_comment = false;
++idx;
}
}
}
if(str.length && !multi_line_comment) {
result.push(str);
str = "";
}
})
return result;
}```Code language: JavaScript (javascript)```

## Remove Comments LeetCode Solution Python

``````class Solution(object):
ans, inComment = [], False
new_str = ""
for c in source:
if not inComment: new_str = ""
i, n = 0, len(c)
while i < n:
if inComment:
if c[i:i + 2] == '*/' and i + 1 < n:
i += 2
inComment = False
continue
i += 1
else:
if c[i:i + 2] == '/*' and i + 1 < n:
i += 2
inComment = True
continue
if c[i:i + 2] == '//' and i + 1 < n:
break
new_str += c[i]
i += 1
if new_str and not inComment:
ans.append(new_str)
return ans``````
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