This Leetcode problem Reformat Department Table LeetCode Solution is done in SQL.

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Reformat Department Table LeetCode Solution

Problem Statement

In SQL,(id, month) is the primary key of this table. The table has information about the revenue of each department per month.
The month has values in [“Jan”,”Feb”,”Mar”,”Apr”,”May”,”Jun”,”Jul”,”Aug”,”Sep”,”Oct”,”Nov”,”Dec”].

Reformat the table such that there is a department id column and a revenue column for each month.

Return the result table in any order.

The result format is in the following example.

Example 1:
Input:

Output:

Explanation: The revenue from Apr to Dec is null. Note that the result table has 13 columns (1 for the department id + 12 for the months).

Reformat Department Table LeetCode Solution MySQL

select 
  id, 
  sum(
    if(month = 'Jan', revenue, null)
  ) as Jan_Revenue, 
  sum(
    if(month = 'Feb', revenue, null)
  ) as Feb_Revenue, 
  sum(
    if(month = 'Mar', revenue, null)
  ) as Mar_Revenue, 
  sum(
    if(month = 'Apr', revenue, null)
  ) as Apr_Revenue, 
  sum(
    if(month = 'May', revenue, null)
  ) as May_Revenue, 
  sum(
    if(month = 'Jun', revenue, null)
  ) as Jun_Revenue, 
  sum(
    if(month = 'Jul', revenue, null)
  ) as Jul_Revenue, 
  sum(
    if(month = 'Aug', revenue, null)
  ) as Aug_Revenue, 
  sum(
    if(month = 'Sep', revenue, null)
  ) as Sep_Revenue, 
  sum(
    if(month = 'Oct', revenue, null)
  ) as Oct_Revenue, 
  sum(
    if(month = 'Nov', revenue, null)
  ) as Nov_Revenue, 
  sum(
    if(month = 'Dec', revenue, null)
  ) as Dec_Revenue 
from 
  Department 
group by 
  id;Code language: SQL (Structured Query Language) (sql)