# Reformat Department Table LeetCode Solution

This Leetcode problem Reformat Department Table LeetCode Solution is done in SQL.

# List of all LeetCode Solution

## Problem Statement

In SQL,(id, month) is the primary key of this table. The table has information about the revenue of each department per month.
The month has values in [“Jan”,”Feb”,”Mar”,”Apr”,”May”,”Jun”,”Jul”,”Aug”,”Sep”,”Oct”,”Nov”,”Dec”].

Reformat the table such that there is a department id column and a revenue column for each month.

Return the result table in any order.

The result format is in the following example.

Example 1:
Input:

Output:

Explanation: The revenue from Apr to Dec is null. Note that the result table has 13 columns (1 for the department id + 12 for the months).

## Reformat Department Table LeetCode Solution MySQL

``````select
id,
sum(
if(month = 'Jan', revenue, null)
) as Jan_Revenue,
sum(
if(month = 'Feb', revenue, null)
) as Feb_Revenue,
sum(
if(month = 'Mar', revenue, null)
) as Mar_Revenue,
sum(
if(month = 'Apr', revenue, null)
) as Apr_Revenue,
sum(
if(month = 'May', revenue, null)
) as May_Revenue,
sum(
if(month = 'Jun', revenue, null)
) as Jun_Revenue,
sum(
if(month = 'Jul', revenue, null)
) as Jul_Revenue,
sum(
if(month = 'Aug', revenue, null)
) as Aug_Revenue,
sum(
if(month = 'Sep', revenue, null)
) as Sep_Revenue,
sum(
if(month = 'Oct', revenue, null)
) as Oct_Revenue,
sum(
if(month = 'Nov', revenue, null)
) as Nov_Revenue,
sum(
if(month = 'Dec', revenue, null)
) as Dec_Revenue
from
Department
group by
id;```Code language: SQL (Structured Query Language) (sql)```
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