Last updated on February 4th, 2025 at 12:26 pm

Here, We see R LinkedIn Skill Assessment Answer. This assessment test consists of 15-20 MCQs to demonstrate your knowledge of your selected skills. MCQs come from different topics – R Data Structures, Data Management, Functions, Operators, and Statistics..

List of all LinkedIn Skills Assessment Answer

R LinkedIn Skill Assessment Answer

Q1. How does a matrix differ from a data frame?

A matrix may contain numeric values only.
A matrix must not be singular.
A data frame may contain variables that have different modes.✔
A data frame may contain variables of different lengths.

Q2. What value does this statement return?

unclass(as.Date("1971-01-01"))

1
365✔
4
12

Q3. What do you use to take an object such as a data frame out of the workspace?

remove()✔
erase()
detach()
delete()

Q4. Review the following code. What is the result of line 3?

xvect<-c(1,2,3)
xvect[2] <- "2"
xvect

[1] 1 2 3
[1] “1” 2 “3”
[1] “1” “2” “3”✔
[1] 7 9

Q5. The variable height is a numeric vector in the code below. Which statement returns the value 35?

height(length(height))
height[length(height)]✔
height[length[height]]
height(5)

Q6. In the image below, the data frame is named rates. The statement sd(rates[, 2]) returns 39. How does R regard Ellen’s product ratings?

sample with replacement
population
trimmed sample
sample✔

Q7. Which choice does R regard as an acceptable name for a variable?

Var_A!
\_VarA
.2Var_A
Var2_A✔

Q8. What is the principal difference between an array and a matrix?

A matrix has two dimensions, while an array can have three or more dimensions.✔
An array is a subtype of the data frame, while a matrix is a separate type entirely.
A matrix can have columns of different lengths, but an array’s columns must all be the same length.
A matrix may contain numeric values only, while an array can mix different types of values.

Q9. Which is not a property of lists and vectors?

type
length
attributes
scalar✔

Q10. In the image below, the data frame on lines 1 through 4 is named StDf. State and Capital are both factors. Which statement returns the results shown on lines 6 and 7?

StDf[1:2,-3]
StDf[1:2,1]✔
StDf[1:2,]
StDf[1,2,]

Q11. Which function displays the first five rows of the data frame named pizza?

BOF(pizza, 5)
first(pizza, 5)
top(pizza, 5)
head(pizza, 5)✔

Q12. You accidentally display a large data frame on the R console, losing all the statements you entered during the current session. What is the best way to get the prior 25 statements back?

console(-25)
console(reverse=TRUE)
history()
history(max.show = 25)✔

Q13. d.pizza is a data frame. It’s a column named temperature contains only numbers. If you extract temperature using the [] accessors, its class defaults to numeric. How can you access temperature so that it retains the class of data.frame?

> class( d.pizza[ , "temperature" ] )
> "numeric"

class( d.pizza( , “temperature” ) )
class( d.pizza[ , “temperature” ] )
class( d.pizza$temperature )
class( d.pizza[ , “temperature”, drop=F ] )✔

Q14. What does c contain?

a <- c(3,3,6.5,8)
b <- c(7,2,5.5,10)
c <- a < b

[1] NaN
[1] -4
[1] 4 -1 -1 2
[1] TRUE FALSE FALSE TRUE✔

Q15. Review the statements below. Does the use of the dim function change the class of y, and if so what is y’s new class?

> y <- 1:9
> dim(y) <- c(3,3)

No, y’s new class is “array”.
Yes, y’s new class is “matrix”.✔
No, y’s new class is “vector”.
Yes, y’s new class is “integer”.

Q16. What is mydf$y in this code?

mydf <- data.frame(x=1:3, y=c("a","b","c"), stringAsFactors=FALSE)

list
string
factor
character vector✔

Q17. How does a vector differ from a list?

Vectors are used only for numeric data, while lists are useful for both numeric and string data.
Vectors and lists are the same thing and can be used interchangeably.
A vector contains items of a single data type, while a list can contain items of different data types.✔
Vectors are like arrays, while lists are like data frames.

Q18. What statement shows the objects in your workspace?

list.objects()
print.objects()
getws()
ls()✔

Q19. What function joins two or more column vectors to form a data frame?

rbind()
cbind()✔
bind()
coerce()

Q20. Review line 1 below. What does the statement in line 2 return?

1 mylist <- list(1,2,"C",4,5)
2 unlist(mylist)

[1] 1 2 4 5
“C”
[1] “1” “2” “C” “4” “5”✔
[1] 1 2 C 4 5

Q21. What is the value of y in this code?

x <- NA
y <- x/1

Inf
Null
NaN
NA✔

Q22. Two variables in the mydata data frame are named Var1 and Var2. How do you tell a bivariate function, such as cor.test, which two variables you want to analyze?

cor.test(Var1 ~ Var2)
cor.test(mydata$(Var1,Var2))
cor.test(mydata$Var1,mydata$Var2)✔
cor.test(Var1,Var2, mydata)

Q23. A data frame named d.pizza is part of the DescTools package. A statement is missing from the following R code and an error is therefore likely to occur. Which statement is missing?

library(DescTools)
deliver <- aggregate(count,by=list(area,driver), FUN=mean)
print(deliver)

attach(d.pizza)✔
summarize(deliver)
mean <- rbind(d.pizza,count)
deliver[!complete.cases(deliver),]

Q24. How to name rows and columns in DataFrames and Matrices F in R?

data frame: names() and rownames() matrix: colnames() and row.names()
data frame: names() and row.names() matrix: dimnames()✔
data frame: colnames() and row.names() matrix: names() and rownames()
data frame: colnames() and rownames() matrix: names() and row.names()

Q25. Which set of two statements-followed by the cbind() function-results in a data frame named vbound?

v1<-list(1,2,3)
v2<-list(c(4,5,6))
vbound<-cbind(v1,v2)

v1<-c(1,2,3)
v2<-list(4,5,6))
vbound<-cbind(v1,v2)

C✔

v1<-c(1,2,3)
v2<-c(4,5,6))
vbound<-cbind(v1,v2)

none

Q26. ournames is a character vector. What values does the statement below return to Cpeople?

Cpeople <- ournames %in% grep("^C", ournames, value=TRUE)

records where the first character is a C
any record with a value containing a C
TRUE or FALSE, depending on whether any character in ournames is C
TRUE and FALSE values, depending on whether the first character in an ournames record is C✔

Q27. What is the value of names(v[4])?

v <- 1:3names(v)<-c("a","b","c")
v[4]<-4

“”✔
d
NULL
NA

Q28. Which of the following statements doesn’t yield the code output below? Review the following code. What is the result of line 3?

x <-c(1,2,3,4)
Output:[1]234

x[c(2, 3, 4)]
x[-1]
x[c(-1, 0, 0, 0)]
x[c(-1, 2, 3, 4)]✔

Q29. Given DFMerged <- merge(DF1, DF2) and the image below, how many rows are in DFMerged?

6
9
3
0✔

Q30. What does R return in response to the final statement?

x<-5:8names(x)<-letters[5:8]
x

e f g h “5” “6” “7” “8”
5 6 7 8
e f g h
e f g h 5 6 7 8✔

Q31. How do you return “October” from x in this code?

x<-as.Date("2018-10-01")

attr()
months(x)✔
as.month(x)
month(x)

Q32. How will R respond to the last line of this code?

fact<-factor(c("Rep","Dem","Dem","Rep"))
fact
[1] Rep Dem Dem Rep
Levels: Rep Dem
fact[2]<-"Ind"

>
[,2]Ind
invalid factor level, NA generated✔
Ind

Q33. What does R return?

StartDate<- as.Date("2020/2/28")
StopDate<- as.Date("2020/3/1")
StopDate-StartDate

“1970-01-02”
time difference of one day
time difference of two days✔
error in x-y: non-numeric argument to binary operator

Q34. What does the expression mtrx * mtrx do?

> mtrx <- matrix(c(3,5,8,4), nrow=2,ncol=2,byrow=TRUE)> newmat <- mtrx * mtrx

it transposes the matrix
it premultiplies the current netwmat row by the newmat column.
it returns the results of a matrix multiplication
It squares each cell in mtrx✔

> newmat
     [,1][,2][1,]925[2,]6416# The `%*%` operator gives matrix multiplication> mtrx %*% mtrx
     [,1][,2][1,]4935[2,]5656

Q35. Which function in R combines different values into a single object?

connect()
concat()
contact()
c()✔

Q36. Which file contains settings that R uses for all users of a given installation of R?

Rdefaults.site
Renviron.site
Rprofile.site✔
Rstatus.site

Q37. If mdf is a data frame, which statement is true ?

ncol(mdf) equals length(mdf).✔
The number of rows must equals the number of columns.
The legnth of any column in mdf may differ from any other column in mdf
All columns must have the same data type.

Q38. A list can contain a list as an element. MyList has five columns, and the third column’s item is a list of three items. How do you put all seven values in MyList into a single vector?

vector(MyList, length = 7)
coerce(MyList, nrows = 1)
unlist(MyList)✔
coerce(MyList, nrows = 7)

Q39. Which strings could be returned by the function ls(path = “^V”)?

ANOVAData, anovadata
VisitPCA, VarX✔
VisitPCA, varx
Xvar, Yvar

Q40. StDf is a data frame. Based on this knowledge, what does this statement return?

StDf[,-1]

all but the first row and first column of StDf
all but the final column of StDf
all but the first column of StDf✔
only the first column of StDf

Q41. Which statement enables you to interactively open a single file?

file.list()
file.select()
file.choose()✔
file.open()

Q42. How are these data types alike: logical, integer, numeric, and character?

Each is a type of data frame.
Each is a type of atomic vector.✔
Each is a type of complex vector.
Each is a type of raw vector.

Q43. What does the MyMat[ ,3] subsetting operation return for this code?

MyMat = matrix(c(7,9,8,6,10,12),nrow=2,ncol=3, byrow =TRUE)

[ ,3]
[1, ] 8
[2, ] 12

B✔

[1] 8 12

[1] 10 12

[ ,3]
[1, ] 10
[2, ] 12

Q44. What does the function power.anova.test return?

the probability of making a Type I error
the probability of not making a Type II error✔
the probability of making a Type II error
the probability of not making a Type I error

Q45. Review the statement below. What is the effect of covariate:factor on the analysis?

result <- lm(outcome ~ covariate + factor + covariate:factor, data = testcoef)

It forces the intercepts of the individual regressions to zero.
It calls for the effect of the covariate within each level of the factor.✔
It calls for the effect of each variable from the covariate to factor in the test.
It forces the covariate to enter the equation before the factor levels.

Q46. A variable whose type is numeric can contain which items?

integers and real values
integers, real, and raw values
real values only✔
integers, real, and logical values

Q47. What is the legitimate name of a data class in R?

property
integer✔
number
variant

Q48. How do you extract the values above the main diagonal from a square matrix named Rmat?

Rmat[upper.tri(Rmat)]✔
upper.triangular(Rmat)
upper.tri(Rmat)
upper.diag(Rmat)

Q49. x is a vector of type integer, as shown in line 1 below. What is the type of the result returned by the statement > median(x)?

x <- c(12L, 6L, 10L, 8L, 15L, 14L, 19L, 18L, 23L, 59L)

numeric
integer
single
double✔

Q50. A list named `a` is created using the statement below. Which choice returns TRUE?

a <- list("10", TRUE, 5.6)

is.list(a[1])✔
is.numeric(a[1])
is.logical(a[1])
is.character(a[1])

Q51. How do you obtain the row numbers in a data frame named pizza for which the value of pizza$delivery_min is greater than or equal to 30?

late_delivery <- pizza$delivery_min >=30
index_late <- index(late_delivery)
index_late

late_delivery <- pizza$delivery_min >=30
rownum_late <- rownum(late_delivery)
rownum_late

C✔

late_delivery <- pizza$delivery_min >=30
which_late <- which(late_delivery)
which_late

late_delivery <- pizza$delivery_min >=30
late <- piza$late_delivery
pizza$late

Q52. Which function returns [1] TRUE FALSE TRUE?

indat <- c("Ash Rd","Ash Cir","Ash St")

grepl(“[Rd|Ave|Dr|St]”, indat)
grepl(“Rd|Ave|Dr|St”, indat)✔
grepl(“Rd,Ave,Dr,St”, indat)
grepl(“[Rd],[Ave],[Dr],[St]”, indat)

Q53. Which statement returns the fourth row of a data frame named fish?

fish[4, ]✔
fish( ,4)
fish(4, )
fish{4, }

Q54. What is the value of csum?

a <- c(1.2, 2, 3.5, 4)
b <- c(1.2, 2.2, 3.5, 4)
csum <-sum(a == b)

8
3✔
0.2
21.6

Q54. A list named a is created using the statement below. Which choice returns TRUE?

a <- list("10", TRUE, 5.6)

is.list(a[1])✔
is.numeric(a[1])
is.logical(a[1])
is.character(a[1])

Q55. What is the result of these three lines of code?

vect1 <-c(1:4)
vect2 <-c(1:2)
vect1 * vect2

[1] 1 4 3 8✔
ERROR
[1] 1 2 3 4 1 2
[1] 1 2 3 4 2 4 6 8

Q56. Which choice returns [1] “2019-09-28”?

format(as.POSIXct(“Sep-28-2019 07:54:31 AM”,format=’%b%d%Y’))
as.POSIXlt(“Sep-28-2019 07:54:31 AM”,format=’%b-%d-%Y’)
as.POSIXct(“Sep-28-2019 07:54:31 AM UTC”)
format(as.POSIXct(“Sep-28-2019 07:54:31 AM UTC”,format=’%b-%d-%Y’))✔

Q57. The variable potus is a character vector, as shown in line 1 below. Wich statement returns the results shown?

1 potus <-c("GHW Bush","Clinton","GW Bush","Obama")

Results:[1]"GHW BUsh""Clinton""Obama"

potus[-“GW Bush”]
potus[1:2 4]
potus[-3]✔
potus[1,2,4]

Q58. A data frame contains two factor -fact1 and fact2- and a numerical outcome variable. Which statement returns results that do NOT include an interaction term?

anova(lm(outcome ~ fact1 : fact2))✔
anova(lm(outcome ~ fact1 * fact2))
anova(lm(outcome ~ fact1 + fact2))
anova(lm(outcome ~ fact1 + fact2 + fact1 : fact2))

Q59. Review line 1 below. What does the statement on line 2 return?

1 myvect <-c(-2,-1,0)2as.logical(myvect)

[1]-2 -1 0
[1]TRUE TRUE FALSE✔
[1]FALSE FALSE TRUE
[1]NA NA NA

Q60. Which option setting can cause difficulty if you want to add to a variable’s possible values after you have designed an object’s initial data structure?

()OPTIONS(colnames(x)<-NULL)
()OPTIONS(max.print=5)
()OPTIONS(continue=”… “,
()OPTIONS(stringAsFactors=TRUE✔

Q61. In the image below, the data frame on lines 1 through 4 is named StDf. StDf contains no factors. Why does the statement on line 6 return “character” while the statement on line 7 returns “data.frame”?

Each value in the first row is a character value, but the values in the third column include both character and numeric values.
By specifying the final row, 3, and no column specified, StDf[3, ] calls for the complete structure.
Columns in a data frame are vectors generally containing a single type of data. Rows in a data frame are lists, but they belong to a structure that has multiple rows: the data frame.✔
Each value in the first column is a character value, but the values in the third row include both character and numeric values.

Q62. Review line 1. What does the statement on line 3 return?

mtrx <- matrix(1:6,3,2)

mtrx[,-1]

[1] 4 5 6✔

Q63. Why does sum(!is.na(pizza$week)) return the number of rows with valid, non-NA values in the column named week?

The exclamation point in !is.na(pizza$week) reverses the meaning of the test it precedes.✔
!is.na(pizza$week) counts the number of NA values in the column.
!is.na(pizza$week) returns a vector of TRUE/FALSE values, in which TRUE is treated as a 0 and FALSE as a 1.
!is.na(pizza$week) counts the number of non-missing values in the column.

Q64. How do you get documentation of an installed and loaded R package named dplyr and packages with dplyr as an alias?

help(dplyr)
? dplyr
?? dplyr✔
Press the F1 key.

Q65. In the image below, the data frame named iris includes a numeric vector named Petal.Length. Do the functions labeled Pair 1 and Pair 2 return the same information?

No, both the length and the class of the returned structures are different.✔
Yes, both pairs of statements return an object with the same length and class.
No, the length is the same but the class is different.
No, the class is the same but the length is different.

Q66. The _ for R is the main feature that makes it different from the original S language.

closure rules
scoping rules✔
environment rules
None of the above

reference

Q67. Which of the following is a base package for R programming?

tools✔
util
lang
All of the above