# Project Employees III LeetCode Solution

This Leetcode problem Project Employees III LeetCode Solution is done in SQL.

# List of all LeetCode Solution

## Problem Statement

(project_id, employee_id) is the primary key of this table. employee_id is a foreign key to `Employee` table. Each row of this table indicates that the employee with employee_id is working on the project with project_id.

employee_id is the primary key of this table. It’s guaranteed that experience_years is not NULL. Each row of this table contains information about one employee.

Write an SQL query that reports the most experienced employees in each project. In case of a tie, report all employees with the maximum number of experience years.

The query result format is in the following example:

Example 1:
Input:

Output:

Explanation: Both employees with id 1 and 3 have the most experience among the employees of the first project. For the second project, the employee with id 1 has the most experience.

## Project Employees III LeetCode Solution MySQL

``````select
p.project_id,
e.employee_id
from
(
select
project_id,
max(experience_years) as max_years
from
Project as p
join Employee as e on p.employee_id = e.employee_id
group by
project_id
) as q,
Project as p,
Employee as e
where
p.project_id = q.project_id
and p.employee_id = e.employee_id
and e.experience_years >= max_years;```Code language: SQL (Structured Query Language) (sql)```

## Project Employees III LeetCode Solution MySQL (Another approach)

``````select
p.project_id,
e.employee_id
from
Project as p,
Employee as e
where
p.employee_id = e.employee_id
and (
p.project_id, e.experience_years
) in (
select
project_id,
max(experience_years) as experience_years
from
Project as p
join Employee as e on p.employee_id = e.employee_id
group by
project_id
)```Code language: SQL (Structured Query Language) (sql)```
Scroll to Top