This Leetcode problem Project Employees II LeetCode Solution is done in SQL.
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Project Employees II LeetCode Solution
Table of Contents
Problem Statement
Column Name | Type |
project_id | int |
employee_id | int |
Project
(project_id, employee_id) is the primary key of this table. employee_id is a foreign key to Employee
table. Each row of this table indicates that the employee with employee_id is working on the project with project_id.
Column Name | Type |
employee_id | int |
name | varchar |
experience_years | int |
Employee
employee_id is the primary key of this table. It’s guaranteed that experience_years is not NULL. Each row of this table contains information about one employee.
Write an SQL query that reports all the projects that have the most employees.
The query result format is in the following example:
Example 1:
Input:
project_id | employee_id |
1 | 1 |
1 | 2 |
1 | 3 |
2 | 1 |
2 | 4 |
employee_id | name | experience_years |
1 | Khaled | 3 |
2 | Ali | 2 |
3 | John | 1 |
4 | Doe | 4 |
Output:
project_id |
1 |
Explanation: The first project has 3 employees while the second one has 2.
Project Employees II LeetCode Solution MySQL
select
project_id
from
Project
group by
project_id
having
count(employee_id) >= (
select
count(employee_id) as cnt
from
Project
group by
project_id
order by
cnt desc
limit
1
);
Code language: SQL (Structured Query Language) (sql)