Last updated on March 10th, 2025 at 10:59 pm
Here, we see the Project Employees II LeetCode Solution. This Leetcode problem is solved using MySQL and Pandas.
List of all LeetCode Solution
Level of Question
Easy

Project Employees II LeetCode Solution
Table of Contents
1. Problem Statement
Column Name | Type |
project_id | int |
employee_id | int |
Project
(project_id, employee_id) is the primary key of this table. employee_id is a foreign key to Employee
table. Each row of this table indicates that the employee with employee_id is working on the project with project_id.
Column Name | Type |
employee_id | int |
name | varchar |
experience_years | int |
Employee
employee_id is the primary key of this table. It’s guaranteed that experience_years is not NULL. Each row of this table contains information about one employee.
Write an SQL query that reports all the projects that have the most employees.
The query result format is in the following example:
Example 1:
Input:
project_id | employee_id |
1 | 1 |
1 | 2 |
1 | 3 |
2 | 1 |
2 | 4 |
employee_id | name | experience_years |
1 | Khaled | 3 |
2 | Ali | 2 |
3 | John | 1 |
4 | Doe | 4 |
Output:
project_id |
1 |
Explanation: The first project has 3 employees while the second one has 2.
2. Code Implementation in Different Languages
2.1 Project Employees II MySQL
select project_id from Project group by project_id having count(employee_id) >= ( select count(employee_id) as cnt from Project group by project_id order by cnt desc limit 1 );