# Maximum Binary Tree LeetCode Solution

Here, We see Maximum Binary Tree LeetCode Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc. with different approaches.

# List of all LeetCode Solution

## Problem Statement

You are given an integer array nums with no duplicates. A maximum binary tree can be built recursively from nums using the following algorithm:

1. Create a root node whose value is the maximum value in nums.
2. Recursively build the left subtree on the subarray prefix to the left of the maximum value.
3. Recursively build the right subtree on the subarray suffix to the right of the maximum value.

Return the maximum binary tree built from nums.

Example 1:

Input: nums = [3,2,1,6,0,5]
Output: [6,3,5,null,2,0,null,null,1]
Explanation: The recursive calls are as follow:
– The largest value in [3,2,1,6,0,5] is 6. Left prefix is [3,2,1] and right suffix is [0,5].
– The largest value in [3,2,1] is 3. Left prefix is [] and right suffix is [2,1].
– Empty array, so no child.
– The largest value in [2,1] is 2. Left prefix is [] and right suffix is [1].
– Empty array, so no child.
– Only one element, so child is a node with value 1.
– The largest value in [0,5] is 5. Left prefix is [0] and right suffix is [].
– Only one element, so child is a node with value 0.
– Empty array, so no child.

Example 2:

Input: nums = [3,2,1]
Output: [3,null,2,null,1]

## Maximum Binary Tree LeetCode Solution C++

``````class Solution {
public:
TreeNode* constructMaximumBinaryTree(vector<int>& nums) {
return constructMaximumBinaryTree(nums,0,nums.size()-1);
}
TreeNode* constructMaximumBinaryTree(vector<int>& nums,int start,int end) {
if(start>end) return nullptr;
int index=-1;
int val=-1;
for(int i=start;i<=end;i++){
if(nums[i]>val){
index=i;
val=nums[i];
}
}
TreeNode* root=new TreeNode(val);
root->left=constructMaximumBinaryTree(nums,start,index-1);
root->right=constructMaximumBinaryTree(nums,index+1,end);
return root;
}
};```Code language: PHP (php)```

## Maximum Binary Tree LeetCode Solution Java

``````class Solution {
public TreeNode constructMaximumBinaryTree(int[] nums) {
for(int n : nums){
TreeNode cur = new TreeNode(n);
while(!stack.isEmpty() && stack.peek().val < n){
cur.left = stack.pop();
}
if(!stack.isEmpty()){
stack.peek().right = cur;
}
stack.push(cur);
}
return stack.isEmpty() ? null : stack.removeLast();
}
}```Code language: PHP (php)```

## Maximum Binary Tree Solution JavaScript

``````var constructMaximumBinaryTree = function(nums) {
if (nums.length === 0) return null;
let max = Math.max(...nums);
let index = nums.indexOf(max);
};```Code language: JavaScript (javascript)```

## Maximum Binary Tree Solution Python

``````class Solution(object):
def constructMaximumBinaryTree(self, nums):
if not nums:
return None
stack = []
for i in nums:
node = TreeNode(i)
lastpop = None
while stack and stack[-1].val < i:
lastpop = stack.pop()
node.left = lastpop
if stack:
stack[-1].right = node
stack.append(node)
return stack[0]```Code language: HTML, XML (xml)```
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