Last updated on October 5th, 2024 at 05:51 pm

Here, We see Compare Version Numbers LeetCode Solution. This Leetcode problem is done in many programming languages like C++, Java, JavaScript, Python, etc. with different approaches.

List of all LeetCode Solution

Compare Version Numbers LeetCode Solution

Problem Statement

Given two version numbers, version1 and version2, compare them.

Version numbers consist of one or more revisions joined by a dot '.'. Each revision consists of digits and may contain leading zeros. Every revision contains at least one character. Revisions are 0-indexed from left to right, with the leftmost revision being revision 0, the next revision being revision 1, and so on. For example 2.5.33 and 0.1 are valid version numbers.

To compare version numbers, compare their revisions in left-to-right order. Revisions are compared using their integer value ignoring any leading zeros. This means that revisions 1 and 001 are considered equal. If a version number does not specify a revision at an index, then treat the revision as 0. For example, version 1.0 is less than version 1.1 because their revision 0s are the same, but their revision 1s are 0 and 1 respectively, and 0 < 1.

Return the following:

• If version1 < version2, return -1.
• If version1 > version2, return 1.
• Otherwise, return 0.

Example 1:
Input: version1 = “1.01”, version2 = “1.001”
Output: 0
Explanation: Ignoring leading zeroes, both “01” and “001” represent the same integer “1”.

Example 2:
Input: version1 = “1.0”, version2 = “1.0.0”
Output: 0
Explanation: version1 does not specify revision 2, which means it is treated as “0”.

Example 3:
Input: version1 = “0.1”, version2 = “1.1”
Output: -1
Explanation: version1’s revision 0 is “0”, while version2’s revision 0 is “1”. 0 < 1, so version1 < version2.

1. Compare Version Numbers LeetCode Solution C++

class Solution {
public:
    int compareVersion(string version1, string version2) {
        int ans = 0;
        int n1 = version1.size(), n2 = version2.size();
        for(int i=0,j=0; i<n1 || j<n2; ++i, ++j) {
            string s1 = "", s2 = "";
            while(i<n1 && version1[i] != '.') {
                if(s1.size() == 0 && version1[i] == '0') {
                    ++i; continue;
                }
                s1 += version1[i++];
            }
            while(j<n2 && version2[j] != '.') {
                if(s2.size() == 0 && version2[j] == '0') {
                    ++j; continue;
                }
                s2 += version2[j++];
            }
            if(s1.size() < s2.size()) return -1;
            else if(s2.size() < s1.size()) return 1;
            ans = s1.compare(s2);
            if(ans < 0) return -1;
            else if(ans > 0) return 1;
        }
        return 0;
    }
};

2. Compare Version Numbers LeetCode Solution Java

class Solution {
    public int compareVersion(String version1, String version2) {
        int temp1 = 0,temp2 = 0;
        int len1 = version1.length(),len2 = version2.length();
        int i = 0,j = 0;
        while(i<len1 || j<len2) {
            temp1 = 0;
            temp2 = 0;
            while(i<len1 && version1.charAt(i) != '.') {
                temp1 = temp1*10 + version1.charAt(i++)-'0'; 
            }
            while(j<len2 && version2.charAt(j) != '.') {
                temp2 = temp2*10 + version2.charAt(j++)-'0';   
            }
            if(temp1>temp2) return 1;
            else if(temp1<temp2) return -1;
            else {
                i++;
                j++;  
            }   
        }
        return 0;        
    }
}

3. Compare Version Numbers Solution JavaScript

var compareVersion = function(version1, version2) {
    var v1Array = version1.split('.');
    var v2Array = version2.split('.');
    var length = Math.max(v1Array.length, v2Array.length);
    for (var i = 0; i < length; i++) {
        var num1 = parseInt(v1Array[i]) || 0;
        var num2 = parseInt(v2Array[i]) || 0;
        if (num1 == num2) {
            continue;
        }
        return num1 > num2 ? 1 : -1;
    }
    return 0;    
};

4. Compare Version Numbers Solution Python

class Solution(object):
    def compareVersion(self, version1, version2):
        main1, _, rest1 = ('0' + version1).partition('.')
        main2, _, rest2 = ('0' + version2).partition('.')
        return cmp(int(main1), int(main2)) or \
            len(rest1+rest2) and self.compareVersion(rest1, rest2)