Last updated on October 9th, 2024 at 10:33 pm

This Leetcode problem Active Businesses LeetCode Solution is done in SQL.

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Active Businesses LeetCode Solution

Problem Statement

(business_id, event_type) is the primary key of this table.
Each row in the table logs the info that an event of some type occured at some business for a number of times.

Write an SQL query to find all active businesses. An active business is a business that has more than one event type with occurences greater than the average occurences of that event type among all businesses.

The result format is in the following example.

Example 1:
Input:

Output:

Explanation:
Average for ‘reviews’, ‘ads’ and ‘page views’ are (7+3)/2=5, (11+7+6)/3=8, (3+12)/2=7.5 respectively.
Business with id 1 has 7 ‘reviews’ events (more than 5) and 11 ‘ads’ events (more than 8) so it is an active business.

1. Active Businesses LeetCode Solution MySQL

select 
  business_id 
from 
  Events e, 
  (
    select 
      event_type, 
      avg(occurences) as avg_occurences 
    from 
      Events 
    group by 
      event_type
  ) as a 
where 
  e.event_type = a.event_type 
  and e.occurences > a.avg_occurences 
group by 
  e.business_id 
having 
  count(*) > 1;